The balanced chemical equation would be as follows:
NaCl + AgNO3 -> NaNO3 + AgCl
We are given the amounts of the reactants. We need to determine first which one is the limiting reactant. We do as follows:
0.0440 mol/L NaCl (.025 L) = 0.0011 mol NaCl -----> consumed completely and therefore the limiting reactant
0.320 mol/L AgNO3 (0.025 L) = 0.008 mol AgNO3
0.0011 mol NaCl ( 1 mol AgCl / 1 mol NaCl) = 0.0011 AgCl precipitate produced
