Answer:
[tex]\text{Axis of symmetry: }x=-2\\\text{Vertex: }x=-2,\ y=10[/tex]
Step-by-step explanation:
[tex]y=-2x^2-8x+2\\\\\text{Solving }y=0:\\-2x^2-8x+2=0\\x=-2\pm\sqrt{5}\text{ (Using the quadratic formula)}\\\\\text{Finding mid-point (x-coordinate):}\\\frac{-2+\sqrt{5}-2-\sqrt{5}}{2}=-2\\\\\therefore\text{Vertex: }x=-2,\ y=10\\\text{Axis of symmetry: }x=-2[/tex]
