Answer:
Cos <B = 3/5
Step-by-step explanation:
Find the diagram attached
From the diagram, we have;
Hypotenuse BC = 80
Opposite to <B = AC =64
Adjacent AB = 48
According to SOH CAH TOA identity
Cos theta = adjacent/hypotenuse
Cos<B = AB/BC
Cos <B = 48/80
Express in its simplest form
Cos <B = (16*3)/(16*5)
Cos <B = 3/5
Hence the ratio of cos<B in its simplest form is 3/5
