Respuesta :

samuelonum1

Answer:

2

Step-by-step explanation:

Given data

We have the function p(x)=(x-1)(x+1)

Let us find

p(2), p(1), and p(0)

p(2)= (2-1)(2+1)

p(2)= (1)(3)

p(2)= 3

P(1)= (1-1)(1+1)

p(1)= 0*1

P(1)= 0

p(0)= (0-1)(0+1)

p(0)= 1

Hence , p(2)+p(1)-p(0)​

=3+0-1

=3-1

=2

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