Answer:
A: 8535360 J
Explanation:
We are given;
mass; m = 13.6 kg
Initial temperature; T1 = -20° C
Final temperature; T2 = 130° C
Specific heat capacity; c = 4184 J/kg.°C
Specific latent heat of fusion; L = 334000 J/kg.
Since we are dealing with change in temperature, then we will use the heat energy formula for specific heat capacity.
Q = mcΔt
Thus;
Q = 13.6 × 4184 × (130 - (-20))
Q = 13.6 × 4184 × 150
Q = 8535360 J
