Respuesta :

Answer:

A.

[tex] {b}^{2} + 3b - 3 = 0[/tex]

Step-by-step explanation:

[tex] {b}^{2} + 3b - 3 = 0 \\ because \: \: {b}^{2} < 4ac \\ {b}^{2} = {3}^{2} = 9 \\ 4ac = 4 \times 1 \times - 3 = - 12 \\ hence : {b}^{2} < 4ac[/tex]