Answer: 40
[tex]\frac{41}{3} -\frac{12}{4} =\frac{41(4)-12(3)}{12} =\frac{164-36}{12} =\frac{128}{12} =\frac{32}{3}\\\\\frac{\frac{32}{3}}{\frac{4}{15} } =\frac{32}{3}*\frac{15}{4} =\frac{8(4)}{3}*\frac{5(3)}{4}=40[/tex]
