Respuesta :
Answer:
54 is the value of (x-y)^2
Step-by-step explanation:
Given:
Equation 1: [tex]x^{2} + y^{2} = 86[/tex]
Equation 2: xy = - 16
Multiply Equation 2 with 2 on both sides: 2xy = -32
Find value of(Equation 3) : [tex](x-y)^2[/tex]
[tex](x-y)^2 = x^{2} + y^{2} + 2xy[/tex]
Put the value of equation 1 and equation 2 in equation 3
i.e. [tex](x-y)^2 = (x^{2} + y^{2}) + (2xy)[/tex]
[tex](x-y)^2 = (86) + (-32)[/tex]
[tex](x-y)^2 = 54[/tex]
