Respuesta :

discipulus

Answer:

[tex]if \: l_{1} \parallel \: l_{2} \Rightarrow \:m_{1} = m_{2} = \frac{7}{9} \\ m = \frac{y-y_{1} }{x - x_{1}} \\ \frac{7}{9} = \frac{y - 6}{x - ( - 2)} \\ y - 6 = \frac{7}{9}(x + 2) \\ y = \frac{7}{9}x + \frac{7}{9}(2) + 6 \\ y = \frac{7}{9}x +( \frac{14}{9} + 6) \\ y = \frac{7}{9}x +\frac{68}{9} \\ \\ method \: 2 \\ \\ y = mx + c \\ 6 = \frac{7}{9}( - 2) + c \\ c = \frac{14}{9} + 6 = \frac{68}{9} \\ y = \frac{7}{9}x +\frac{68}{9}[/tex]

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