Respuesta :

Answer:

(√3 tan x + 1) / (√3 - tan x)

Step-by-step explanation:

[tex]tan (x+\frac{\pi }{6})\\= \frac{tan x+\frac{1}{\sqrt{3} } }{1-\frac{tan x}{\sqrt{3} } } \\= \frac{\sqrt{3} tan x + 1}{\sqrt{3} -tan x}[/tex]