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23-11-2021
Mathematics

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Solve the attached problem please

Solve the attached problem please class=

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Аноним Аноним

23-11-2021

Answer:

41910.

Step-by-step explanation:

We can calculate this by first finding the sum for k = 1 to 50 then subtracting the sum for k = 1 to 14.

We use the formula (1/6)n(n+1)(2n+1)

So for 1 to 50 its 1/6 * 50* 51 * 101 = 42925

and for 1 to 14 it comes to 1/6*14*15*29 = 1015

So the answer is 41910.

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