akhilchokka2872007 akhilchokka2872007
  • 25-11-2021
  • Mathematics
contestada

If the point (2K-3, K+2) lies on the graph of the equation 2x+y+14=0, find the value of k.?​

Respuesta :

vivianngn96 vivianngn96
  • 25-11-2021

Answer:

k = -2

Step-by-step explanation:

Substitute 2k-3 for x and k+2 for 2

2x + y + 14 =0

2(2k-3) + (k + 2) + 14 = 0

4k - 6 + k + 2 + 14 = 0

4k + k - 6 + 2 + 14 = 0

5k + 10 = 0

5k + 10 - 10 = 0 - 10

5k = -10

[tex]\frac{5k}{5} = \frac{-10}{5}[/tex]

k = -2

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