umanaisabel07 umanaisabel07
  • 22-12-2021
  • Physics
contestada

9) when the distance was one fourth as much, what happened to the force between the objects?

in this case (G=6.67E-11)

Respuesta :

leena
leena leena
  • 23-12-2021

Hi there!

Recall Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = \frac{Gm_1m_2}{r^2}}[/tex]

G = Gravitational Constant

m1, m2 = mass of objects (kg)

r = distance between objects (m)

There is an INVERSE-SQUARE relationship between the gravitational force and the distance between the objects, so:

[tex]F_g = \frac{Gm_1m_2}{(\frac{1}{4}r)^2} = F_g = \frac{Gm_1m_2}{\frac{1}{16}r^2}[/tex]

[tex]= 16G\frac{m_1m_2}{r^2} = 16F_g[/tex]

Thus, the gravitational force between the objects would INCREASE by a factor of 16.

Answer Link

Otras preguntas

Triangle ABC is similar to triangle XYZ by the AA Similarity Postulate. Also, m∠A = 39° and m∠C = 24°. What is m∠Y?
The use of credit in the U.S. has both positive and negative consequences for economic growth. Which of the following describes a case in which the use of credi
What is the exact volume of the cone 4 in and 7 in
why was embalming important to egyptians?
Which is the best estimate for the weight of a stapler 4 ounces for pounds 4 inches or feet
Comparing and Extending Ratios Pam and her brother have a pattern to saving money. Pam has saved $40 and her brother has saved $100. Pam says that this mean
what is the lcd of 3/10an -4/15?
what did leaders of Rhode Island believe would happen to religion if church and state were connected
what is 32 over 64 reduced too
What is the solution to the system of equations? 4x + y = 2 x - y = 3 ( ______ , ______ )