craigismadsus
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  • 22-01-2022
  • Mathematics
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Find the equation of the line that contains the point (-1,-6) and is parallel to the line 5x+3y=8. Write the equation in slope-intercept form.

Find the equation of the line that contains the point 16 and is parallel to the line 5x3y8 Write the equation in slopeintercept form class=

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rspill6
rspill6 rspill6
  • 24-01-2022

Answer:

y = -(5/3)x -(23/3)

Step-by-step explanation:

Rewrite the given equation is standard slope-intercept format: y = mx + b

5x + 3y = 8

3y = -5x + 8

y = -(5/3)x + (8/3)

A parallel line will have the same slope:  -(5/3)

y = -(5/3)x + b

We need to find a b that will force the line through point (-1,-6).

y = -(5/3)x + b

-6 = -(5/3)*(-1) + b

-6 - (5/3) = b

b = -(23/3)

y = -(5/3)x -(23/3)

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