DarkMasterBG DarkMasterBG
  • 24-01-2022
  • Mathematics
contestada

Find the value of x in the equation:
x^2 + 4 = 12

Respuesta :

vortexdevity
vortexdevity vortexdevity
  • 24-01-2022

Answer:

[tex] \sqrt{8} = 2 \sqrt{2} [/tex]

Step-by-step explanation:

In the equation we must first move 4 to the other side and change its sign

x^2 + 4 = 12

x^2 = 12 - 4

x^2 = 8

Then we find x:

x =

[tex]x = \sqrt{8} = \sqrt{2 \times 2 \times 2} = \sqrt{ {2}^{2} \times 2 } = 2 \sqrt{2} [/tex]

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