Answer:
8xy³(2y²+7)
Step-by-step explanation:
[tex]( \frac{16 {x}^{2} \times 2 {y}^{5} }{4x {y}^{2} } + 28xy) \times 2 {y}^{2} \\ = (8x {y}^{3} + 28xy) \times 2 {y}^{2} \\ = (4xy(2 {y}^{2} + 7)) \times 2 {y}^{2} \\ = 8x {y}^{3} (2 {y}^{2} + 7)[/tex]
