alease1637 alease1637
  • 22-05-2022
  • Mathematics
contestada

Find the vertex and the axis of symmetry of the graph of the function
f(x)=3(x+1)^2

Respuesta :

rdacoder
rdacoder rdacoder
  • 22-05-2022

Answer: vertex (-1, 0) axis of symmetry -> x = -1

Step-by-step explanation:

f(x) = [tex]3(x+1)^{2}[/tex]

to find the vertex do

x+1 = 0

to find the x value

x = -1

plug -1 into the equation

f(-1) = [tex]3(-1+1)^{2}[/tex]

f(-1) = 3(0)

f(-1) = 0

Therefore, the vertex is (-1, 0)

The axis of symmetry is

x = -1

because that is where the lowest x value is

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