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There were 16 teams that competed in men's ice hockey at the Salt Lake City Olympics of 2002.
Find the number of permutations for the gold, silver, and bronze metals at the awards ceremony.

Respuesta :

Answer:

3360.

Step-by-step explanation:

That would be the number of permutations of 3 from 16.

= 16P3

= 16!/(16-3)!

= 16*15*14

= 3360

Answer:

3Β 360 permutations

Step-by-step explanation:

the number of permutations :

16P3 = 16 Γ— 15 Γ— 14 = 3Β 360

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