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A 500. gram cart with a speed of 0.360 m/s hits a barrier and bounces back with a return velocity of -0.240 m/s. what is its change in momentum?
a. 60.0 kg*m/s
b. 0.300 kg*m/s
c. -0.300 kg*m/s
d. .0600 kg*m/s
e. -.0600 kg*m/s

Respuesta :

Eduard22sly

The change in the momentum of the cart,given the data is 0.06 Kgm/s (Option D)

What is momentum?

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

Change in momentum = mass (final velocity - initial velocity)

How top determine the change in the momentum

From the data given above, the following data were obtained:

  • Mass (m) = 500 g = 500 / 1000 = 0.5 Kg
  • Initial velocity (u) = 0.360 m/s
  • Final velocity (v) = -0.240 m/s.
  • Change in momentum =?

Change in momentum = m(v + u) (renounce)

Change in momentum = 0.5 (-0.24 + 0.36)

Change in momentum = 0.5 × 0.12

Change in momentum = 0.06 Kgm/s

Learn more about momentum:

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