Respuesta :

[tex]2\sqrt{2}\cdot \sqrt{12} ~~ \begin{cases} 12=2\cdot 2\cdot 3\\ \qquad 2^2\cdot 3 \end{cases}\implies 2\sqrt{2}\cdot \sqrt{2^2\cdot 3}\implies 2\sqrt{2}\cdot 2\sqrt{3} \\\\\\ (2\cdot 2)\sqrt{2\cdot 3}\implies 4\sqrt{6}[/tex]

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