Given the following trinomial:
[tex]x^2-13x+42[/tex]
To factor the trinomial, we need two numbers the product of them = 42
And the sum of them = -13
Two of the numbers of factors of 42 = -6, and -7
So, the factor of the trinomial will be as follows:
[tex]x^2-13x+42=(x-6)(x-7)[/tex]
So, the answer will be option B. x - 7
