DalilaK186404 DalilaK186404
  • 25-10-2022
  • Mathematics
contestada

The coordinates of rhombus abcd are a(-4,-2) b(-2,6) c(6,8) d(4,0). What is the area of the rhombus

Respuesta :

EdselL227641 EdselL227641
  • 25-10-2022

First, graph the rhombus:

Area of a rhombus = Product of diagonals / 2

Find the length of the diagonals:

Distance between points:

[tex]\sqrt[\placeholder{⬚}]{(x2-x1)^2+(y2-y1)2^}[/tex]

Diagonal AC

[tex]AC=\sqrt[\placeholder{⬚}]{(6-(-4))^2+(8-(-2))^2}[/tex]

AC= 10√2

Diagonal BD

[tex]BD=\sqrt[\placeholder{⬚}]{(4-(-2))^2+(0-6)^{^2}}[/tex]

BD=6√2

Area= AC x BD / 2

Area = [(10√2) x (6√2)]/2

Area = 60

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