Answer:
Explanation:
Given:
[tex]-3x^2+4x+1=0[/tex]
To find:
the value of x using the quadratic formula
The quadratic formula is given as:
[tex]$x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$[/tex]
where a = -3, b = 4, c = 1
[tex]\begin{gathered} x\text{ = }\frac{-4\pm\sqrt{(4)^2-4(-3)(1)}}{2(-3)} \\ \\ x\text{ = }\frac{-4\pm\sqrt{16+12}}{-6} \\ \\ x\text{ = }\frac{-4\pm\sqrt{28}}{-6} \end{gathered}[/tex][tex]undefined[/tex]
