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2: A game is played by tossing a single coin onto a square table. The square is 25 inches o each side, and the coin has a radius of 10 inches (it's old fashioned). If the coin lands entirely on the table (nothing hanging off the edge), the player wins a prize. What fraction of the table can the center point of the coin land on so that the player wins a prize?

Respuesta :

Find the area of the square table:

[tex]\text{Area of the square = }L^2=25^2=625in^2[/tex]

Find the area of the coin (area of a circle):

[tex]\text{Area of coin= }\pi r^2=\pi10^2=314.16in^2[/tex]

To find the fraction of the table the center point of the coin lands, we have:

[tex]\frac{Area\text{ of coin}}{\text{Area of table}}[/tex][tex]=\frac{314.16}{625}\text{ = }0.50[/tex]

Since we are to leave the answer in fraction, we have:

[tex]\frac{5}{10}=\text{ }\frac{1}{2}[/tex]

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