Respuesta :

Given

Table of names

Procedure

Names end with an E

Gabe

Steve

The probability would be independent and equal to:

[tex]\begin{gathered} \frac{2}{6}\cdot\frac{2}{6} \\ \frac{4}{36} \\ \\ \frac{1}{9} \end{gathered}[/tex]

The probability would be 1/9

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