RyahH649409 RyahH649409
  • 25-10-2022
  • Mathematics
contestada

Find the equation of the tangent line to the curve y = x^3- 4x - 5 at the point (2, -5).Tangent Line Equation:

Respuesta :

AshaadT88783 AshaadT88783
  • 25-10-2022

Let's find the derivative of y:

[tex]\begin{gathered} y=x^3-4x-5 \\ \frac{dy}{dx}=3x^2-4 \end{gathered}[/tex]

Evaluate the derivative for x = 2:

[tex]\frac{dy}{dx}\begin{cases} \\ x=2\end{cases}=3(2)^2-4=12-4=8[/tex]

Now, we have the slope, let's use the point-slope formula to find the equation:

[tex]\begin{gathered} y-y1=m(x-x1) \\ _{\text{ }}where\colon \\ (x1,y1)=(2,-5) \\ m=8 \\ y+5=8(x-2) \\ y+5=8x-16 \\ y=8x-21 \end{gathered}[/tex]

Answer:

y = 8x - 21

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