Given:
Find: Area of the figure.
Sol:
The area of Triangle ABH is:
Area
[tex]\text{ Area=}\frac{1}{2}\times\text{ Base}\times\text{ height}[/tex]
In triangle is:
Base = (9-3)
Height = 8
So Area of ABH is:
[tex]\begin{gathered} \text{ Area=}\frac{1}{2}\times6\times8 \\ \\ =24 \end{gathered}[/tex]
Area of rectangle BDFH so,
[tex]\text{ Area=Length}\times\text{ width}[/tex]
Width = 8
[tex]undefined[/tex]
