We are given the following function
[tex]f(t)=\frac{2t}{3}[/tex]We are asked to find out the value of t which results in f(t) = 64
Let us substitute f(t) = 64 into the above function and solve for t
[tex]\begin{gathered} f(t)=\frac{2t}{3} \\ 64=\frac{2t}{3} \\ 3\cdot64=2t \\ 192=2t \\ \frac{192}{2}=t \\ 96=t \\ t=96 \end{gathered}[/tex]Therefore, the value of t is 96
