Given : 30 60 90 triangle as shown in the following figure :
As shown : the hypotenuse of the triangle = 28√5
The side length opposite to the angle 30 =
[tex]\frac{1}{2}\cdot28\sqrt[]{5}=14\sqrt[]{5}[/tex]
The side length opposite to the angle 60 =
[tex]\frac{\sqrt[]{3}}{2}\cdot28\sqrt[]{5}=\frac{28}{2}\sqrt[]{3\cdot5}=14\sqrt[]{15}[/tex]
