Solution
For this case we can do the following:
[tex]\frac{\frac{2}{x}-\frac{4}{y}}{-\frac{5}{y}+\frac{3}{x}}[/tex]
We can start with the numerator and we have:
[tex]\frac{2}{x}-\frac{4}{y}=\frac{2y-4x}{xy}=\frac{2(y-2x)}{xy}[/tex]
For the denominator we have:
[tex]-\frac{5}{y}+\frac{3}{x}=\frac{3y-5x}{xy}[/tex]
And replacing we got:
[tex]\frac{\frac{2(y-2x)}{xy}}{\frac{3y-5x}{xy}}=\frac{2(y-2x)}{3y-5x}[/tex]
Then the correct answer would be:
[tex]\frac{2(y-2x)}{3y-5x}[/tex]
