KlarkY442752
KlarkY442752
25-10-2022
Mathematics
contestada
solve sin2x-sin4x +sin6x=0
Respuesta :
JoshawnV378685
JoshawnV378685
25-10-2022
Remember that
[tex]\sin 2\theta=2\sin \theta\cos \theta[/tex]
Therefore,
[tex]\begin{gathered} \sin 2x-\sin 4x+\sin 6x=0 \\ \Rightarrow2\sin x\cos x-2\sin 2x\cos 2x+2\sin 3x\cos 3x=0 \end{gathered}[/tex]
Then,
[tex]undefined[/tex]
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