woodhamtommi woodhamtommi

27-03-2017
Mathematics

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find the angle there with sectheta=2 exactly over 0

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jdoe0001 jdoe0001

27-03-2017

[tex]\bf sec(\theta)=\cfrac{2}{0}\iff \cfrac{1}{cos(\theta)}=\cfrac{2}{0}\implies \cfrac{1\cdot 0}{2}=cos(\theta)\implies cos^{-1}(0)=\theta \\\\\\ \theta= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}[/tex]

on the interval [0, 2π]

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