Respuesta :

MoSikder
Start by using trig to find the length of the line LJ

The triangle KJL (big right angled triangle) has been given the following dimensions

Hypotenuse = [tex]8 \sqrt{2} [/tex]
The adjacent angle is 30 degrees

Since we have the hypotenuse and the  angle we must use the equation 
opposite = Sin(angle) x Hypotenuse

Opposite= sin30 x [tex]8 \sqrt{2} [/tex]

Opposite= [tex]4 \sqrt{2} [/tex]

Therefore line LJ is [tex]4 \sqrt{2} [/tex]


Now look at the smaller right angled triangle (LMJ) 

Hypotenuse is the line LJ which is [tex]4 \sqrt{2} [/tex]

The adjacent angle is 45

Since we have hypotenuse and angle we must use the equation opposite = sin(angle) * h

therefore 
x= [tex]4 \sqrt{2} [/tex] * sin45= 4


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