Respuesta :

[tex]\bf n^{th}\textit{ term of a geometric sequence}\\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} a_1=\textit{first term}\\ r=\textit{common ratio}\\ n=n^{th}\ term\\ -------\\ a_1=-2\\ r=-5\\ n=4 \end{cases}\implies a_4=(-2)(-5)^{4-1}[/tex]

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