Respuesta :

RickyChen
f(x) = 16^x = 8^2x
g(x) = 16^1/2x = 8^x

So you can see the relationship. They are all of the type a^bx form, with same base of a, f(x) will have larger increasing rate.

The output values of g(x) are the square root of the output values of f(x) for the same value of x