rlantier10 rlantier10

22-04-2024
Physics

contestada

What is the voltage drop across a 50 omega resistor when a current of .1 amps flow through it

Respuesta :

olumideolawoyin olumideolawoyin

22-04-2024

Answer:

5v

Explanation:

According to Ohm's law,

V = IR, where V = voltage, I = current and R is the resistor. Therefore,

V = IR = 0.1 × 50 = 1/10 × 50 = 5v

Voltage drop = 5v

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