Answer:
Explanation:
pOH = -log[OH-]
Simple as that
if you have pOH, and want to find the concentration, just do 10^-pOH
Bonus class just for you:
-If you have [OH-] and you want to find the pH, its the same but once finding pOH, you do 14-pOH = pH
-[OH-] if you have [H+] or the opposite, just divide the concentration by 1*10^-14. This is known as the dissociation constant of water.
