dixonandrea03 dixonandrea03

22-09-2017
Mathematics

contestada

The perimeter of a rectangular field is 380yd. The length is 50 yd longer than the width. Find the dimensions.

Respuesta :

texaschic101 texaschic101

22-09-2017

P = 2(L + W)
P = 380
L = W + 50

380 = 2(W + 50 + W)
380 = 2(2W + 50)
380 = 4W + 100
380 - 100 = 4W
280 = 4W
280/4 = W
70 = W <=== width is 70 yds

L = W + 50
L = 70 + 50
L = 120 <=== length is 120 yds

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