Answer is: 366,3 g of zinc oxide can be produced.
Chemical reaction: 2Zn + O₂ → 2ZnO.
n(Zn) = 4,5 mol.
m(ZnO) = ?
Frome reaction: n(Zn) : n(ZnO) = 2 : 2 (1 : 1).
n(ZnO) = n(Zn) = 4,5 mol.
m(ZnO) = n(ZnO) · M(ZnO).
m(ZnO) = 4,5 mol · 81,4 g/mol.
m(ZnO) = 366,3 g.
n - amount of substance.
