Respuesta :

gustanika
In the quadratic equation y = ax² + bx + c, the axis of symmetry can be determined with
x = -b/2a

Solution:
Identify the coefficient of the quadratic equation y = 3x² - 6x - 4
a = 3
b = -6
c = -4

The axis symmetry will be
x = -b / 2a
x = -(-6) / 2(3)
x = 6/6
x = 1

The axis of symmetry is x = 1

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