shelovesnick444
shelovesnick444
26-01-2018
Mathematics
contestada
(3a^2–7a^2-3a^4)+(4a^2-a^4-4a)
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iiKajanaii
iiKajanaii
26-01-2018
Rearrange the equation
(3a^2–7a^2-3a^4)+(4a^2-a^4-4a)
(-3a^4 +3a^2 - 7a^2) + (-a^4 + 4a^2 - 4a)
-4a^4 - 4a
-4a ( a^3 + 1)
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Catya
Catya
26-01-2018
There is no need for parenthesis, so you can just combine like terms.
[tex]3 a^{2} -7 a^{2} - 3a^{4} + 4 a^{2} - a^{4} -4a \\ \\ = -4 a^{4} - 4a \\ \\ = -4a( a^{3} + 1)[/tex]
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