An electrostatic force of 81N exist between a charge of +2 x 10-5C and a second charge of +4.5 x 10-4C. What is the distance between the two charges? Is it attractive or repulsive?
Coulomb's law states that F = k(q1)(q2)/r^2, where k = 9 x 10^9 N-m^2/C^2 From the given: 81 = (9x10^9)(2x10^-5)(4.5x10^-4)/r^2 r^2 = 1 r = 1 m Since both charges have the same sign (positive), the force is repulsive (like charges repel). Therefore there is a 1-m distance between the two charges, and the force is repulsive.