How many distinct pairs of perfect squares differ by 35? (the pair $a, b$ is the same as the pair $b, a$.)?

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22-02-2018
Mathematics

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How many distinct pairs of perfect squares differ by 35? (the pair $a, b$ is the same as the pair $b, a$.)?

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sqdancefan sqdancefan · Answer 1 · 2018-02-22T11:54:04+01:00

sqdancefan sqdancefan

22-02-2018

35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35

One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}

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zetshia zetshia · Answer 2 · 2021-11-29T23:13:16+01:00

zetshia zetshia

29-11-2021

Answer:

2

Step-by-step explanation:

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