chuyito4157 chuyito4157
  • 26-02-2018
  • Chemistry
contestada

A 5.63 g sample of solid gold is heated from 21.0 ºC to 32.0 ºC. How much energy (in J and cal) is required?

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superman1987
superman1987 superman1987
  • 07-03-2018
According to q formula:
q = M C ΔT
when q is the energy required in Joule
M is the mass per kilogram=5.63 g /1000 = 0.00563 Kg
C is the specific heat capacity of the gold J(Kg-K) =  125.6 J(Kg-K)(should be given in the specific heat capacity table)
ΔT is the change in the temperature = (32 - 21) = 11 C°
∴q = 0.00563 * 125.6 * 11 =  7.78 J     = 1.86 Cal  
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