jonathanratz jonathanratz
  • 26-02-2018
  • Mathematics
contestada

what is the horizontal asymptote of the function f(x)=-2x/x+1

Respuesta :

jdoe0001 jdoe0001
  • 26-02-2018
since the degree of the numerator is the same as the degree of the denominator, then the horizontal asymptote is at

[tex]\bf f(x)=\cfrac{\underline{-2} x}{\underline{1} x+1}\implies \stackrel{horizontal~asymptote}{y=\cfrac{-2}{1}\implies y=-2}[/tex]
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