[tex]10 \frac{3}{4} - 7 \frac{1}{4} \\ \\ \frac{10 \times 4 + 3}{4} -7 \frac{1}{4} \\ \\ \frac{43}{4} - y \frac{1}{4} \\ \\ \frac{43}{4} - \frac{7 \times 4 + 1}{4} \\ \\ \frac{43}{4} - \frac{29}{4} \\ \\ \frac{43-29}{4} \\ \\ \frac{14}{4} \\ \\ \frac{7}{2} \\ \\ 3 \frac{1}{2} \\ \\ Answer: \fbox {3 \ 1/2} \ or \ \fbox {3.5} [/tex]
