the balanced equation for the above reaction is as follows;
4HCl + Oâ‚‚ ---> 2Hâ‚‚O + 2Clâ‚‚
stoichiometry of HCl to Oâ‚‚ is 4:1
number of HCl moles present - 63.1 g / 36.5 g/mol = 1.73 mol
number of Oâ‚‚ moles present - 17.2 g / 32 g/mol = 0.54 mol
if HCl is the limiting reactant; then number of Oâ‚‚ moles = 1.73/4 = 0.43 mol
There are 0.54 mol present and only 0.43 mol are required to react. Therefore HCl is the limiting reactant and Oâ‚‚ is in excess.