Brendee Brendee
  • 25-03-2018
  • Mathematics
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Solve by completing the square 9x^ - 18 x +93= -6

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Аноним Аноним
  • 25-03-2018
[tex]9x^2 - 18 x + 93= -6[/tex]

take away 93 from both sides
[tex]9x^2 - 18 x = - 99[/tex]

Divide by 9 through
[tex]x^2 - 2 x = - 11[/tex]

Add (b/2)^2 to form perfect square
[tex]x^2 - 2 x + ( \frac{2}{2} )^2 = - 11 + ( \frac{2}{2} )^2 [/tex]

Form perfect square
[tex](x - 1)^2 = - 10 [/tex]

Square root both sides to find x
[tex]x - 1 = \pm \sqrt{-10} [/tex]

add 1 on both sides
[tex]x = 1+ i\sqrt{10} \ or \ 1- i\sqrt{10} [/tex]


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