Solving the expression by completing square method we shall have:
x^2-4x+14=13
this can be written:
x^2-4x=13-14
x^2-4x=-1
but
c=(b/2a)^2
c=(-4/2*1)^2=4
thus we shall have:
x^2-4x+4=-1+4
factoring the LHS we get:
(x-2)(x-2)=3
(x-2)^2=3
getting the square root of both sides:
x-2=+/-√3
hence
x=2+/-√3
Thus the equivalent equation will be: x^2-4x+4=3
