jetblackcap
jetblackcap
23-04-2018
Mathematics
contestada
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Аноним
Аноним
23-04-2018
∠ADC = 112°
∠ADC =6x + 7 + 12x - 3
Equate both:
6x + 7 + 12x - 3 = 112
Solve for x :
6x + 7 + 12x - 3 = 112
Combine like terms:
18x + 4= 112
Take away 4 from both sides:
18x = 108
Divide both sides by 18:
x = 6
Find ∠ADB:
6x + 7 = 6(6) + 7 = 43
Answer: ∠ADB = 43°
Answer Link
Supernova
Supernova
23-04-2018
If m∠ABC = 112°, then m∠ADB + m∠BDC must equal 112°.
Make
m∠ADB + m∠BDC = 112.
6x + 7 + 12x - 3 = 112
18x + 4 = 112
18x = 108
x = 6
Now plug x into 6x + 7 to find m∠ADB.
6(6) + 7 = 43
m∠ADB = 43°
Answer Link
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